1.Horizontal velocity
vₓ = 25.00 cos(45.00°) = 17.68 m/s
Horizontal velocity is constant without air resistance.
Motion · Beginner · Real physics
Projectile Motion
Launch an object, follow its trajectory, and explore velocity, gravity, range and height.
WORKED SOLUTION
The maths behind the model
2.Vertical velocity
vᵧ₀ = 25.00 sin(45.00°) = 17.68 m/s
Gravity slows the ascent and accelerates the descent.
3.Time and range
T = 2vᵧ₀/g = 3.60 s; R = vₓT = 63.71 m
These results assume equal launch and landing heights.
Check your answer
At landing, height returns to zero. Changing mass should not change the ideal path.